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A 3000 kg truck moving at a speed 72 km per hr stops after covering some distance ,the force applied by brakes is 24000 N . compute the distance covered

and work done by this force ?


(74[tex]^{2} *3000)/(2*24000)= 3422.5

the equation derived from v x^{2} =u x^{2} +2aS
=> S=u ^2/2a
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