Answers

2016-03-29T22:10:58+05:30
Volume of Cone = 1/3 x Π x r² x h
 r = 7m    h = 12m
  ∴  1/3 x 22/7 x 7 x 7 x 12
   =  616 m³
 hence the amount of air insde is 616m³
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2016-03-30T20:29:29+05:30
Volume of a cone = 1\3.π.r².h
where π = 22\7
r = 7m
h = 12m
therefore volume of the cone = 1\3×22\7×7×7×12
= 616cm³
therefore the amount if air present inside the cylinder = 616
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