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## Answers

Now, sum of the numbers : a+ar+ar² = 57 ----------- (i)

" product of numbers : a*ar*ar² = 343 -----------(ii)

a³r³ = 343

(ar)³ = 343

on comparing, we get

**ar = 7 ⇒ a = 7/r**

putting the value of ar in eq. (i)

7/r + 7 + 7r = 57

7r² - 50r - 7 = 0

7r² -49r - r - 7 = 0

7r (r-7) +1 (r-7) = 0

∴

**r = 7 & a = 1**

Hence,

**numbers are 1, 7, 49**