Answers

2016-03-31T16:17:08+05:30
Rn = n^{2} h^{2} /  4 \pi^{2} m e^{2} Z
 Where h= Plank's constant 
             m=mass of electron
              e=charge of electron
              Z=atomic number
This gives us  R{n}= 0.529* n^{2} / Z
By substituting the values of n=3 and Z=3, we get 
(0.529*3^2)/3=
0.529*3=1.587 angstroms

Hope this helps!!
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