Answers

2016-04-01T12:52:16+05:30
No of diagonals of a polygon = n(n-3)/2
where n is no of sides.
here n = 8
substitute values
we have,
8×5/2 = 20
so octagon has 20 diagonals
0
2016-04-01T13:00:12+05:30
Number of diagonals = [n(n-3)]/2

where
n=sides
octagon has 8 sides
its equals to [8(8-3)]/2
so [40]/2
so answer is 20
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