Answers

2016-04-01T20:36:07+05:30
Let two numbers be x and y
then, x+y=34
x=34-y...........(1)
also
x×y= 128.........(2)
now you can solve 1 and 2 by substitution method to get the answer
0
2016-04-01T21:06:20+05:30
Let two numbers be x. And y........... ATQ---- x+y= 34......x=34-y ---eq. 1 and xy= 128---eq. 2..... Put value of x in eq. 2.......... Therefore .. (34-y)×y =128.......34y-y^2= 128................ -y^2+34y-128=0....... Take -1 in common .... Now y^2 -34y+128=0... ... Now you can do it with any method.... Try
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