Answers

2016-04-02T14:44:05+05:30
Power of the bulb, P=60 W=60/1000 KW=0.06 KW

time, t = 6 h

energy consumed by bulb per day =P×t =0.06 KW × 6 h =0.36 KWh
                                                       =0.36 units
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