Answers

2016-04-18T01:11:50+05:30
In triangleAPB nd tri.BRQ
angleAPB=angleBSR (alternate angles)
PB=BS(given-B is mid pt.)
anglePBA=angleSBR(vertiacally opp. angles)
triangleAPB and tri. BRQ are congruent by ASA.
=>AP=SR (by cpct)__(1)
PQRS is a parallelogram,
=>PQ=SR (opp. sides of a parallelogram are equal)__(2)
according to eq. (1) and (2)
AP=SR
PQ=SR
=>AP=PQ.
AP+PQ=AQ
PQ+PQ=AQ (AP=PQ)
2PQ=AQ
hence proved!
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