Answers

2014-03-04T22:50:24+05:30
Putting n=1 
 T_{1} = 8
Putting n=2 
 T_{2}=12  
 d= T_{2}-T_{1}=12-8=4
a=8
d=4
T_{n}= a + (n-1)d = 8+(n-1)4= 8+ 4n - 4 = 4+4n = 4(n+1)
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