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Distance covered by the particle = 3+4+6 = 13 m

Displacement =  \sqrt{3^{2}+4^{2}  }
                         =  \sqrt{25}
                         = 5
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The Brainliest Answer!
Total distance: 3m+4m+6m=13m
Total displacement =shortest distance from initial positon to final position.
according to the question you can plot the diagram as here attached file.
Usign pythagoras theorem.
you can find the displacement as:3²+3²=(displacement)²

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