Answers

2016-04-10T12:34:40+05:30
Consider that m=2.square of 2=4, (2×2=4).
5m=5 (2)=10
4 not equals to 10

5m+1=5 (2)+1=11
4 not equals to 11

5m+4=5 (2)+4=14
14 is also not equals to 4.


If we take 5 as "m" then the square of 5=25,which satisfies the condition 5m
hence proved.

only 5 is the number which can satisfies the condition 5m. There is no other number which can satisfies the conditions 5m,5m+1,5m+4.

0