Answers

2016-04-10T13:09:14+05:30
Volume of water in cubical tank = a³ = 2³ =8cm³
Dimensions of cuboid ,
l = 2.5 m
b = 2 m
h = 2m

volume of cuboid = lbh = 2.5 × 2 × 2 = 10 cm ³

volume of cuboid left when water is poured from cubical tank = 10 - 8 = 2cm³

2.5 × 2 × h = 2
h =  \frac{1}{2.5}
h =  \frac{1}{\frac{5}{2}}
h =  \frac{2}{5}
h = 0.4 m
the depth of tank which will remain empty = 0.4 m
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