Log in to add a comment

Log in to add a comment

The Brainliest Answer!

Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.

Let the points be A(1,1) , B(13,1) and C(13,6).

By Distance Formula,

AB² = (1 - 13)² + (1 - 1)²

= (-12)² + 0²

= 144 + 0

∴AB² = 144

BC² = (13 - 13)² + (1 - 6)²

= 0² + (-5)²

= 0 + 25

∴BC² = 25

AC² = (1 - 13)² + (1 - 6)²

= (-12)² + (-5)²

= 144 + 25

∴AC² = 169

Now, AB² + BC² = 144 + 25

= 169

= AC²

∴AB² + BC² = AC²

Thus, (1,1) , (13,1) and (13,6) are the vertices of a triangle, and that too a right angled triangle.

By Distance Formula,

AB² = (1 - 13)² + (1 - 1)²

= (-12)² + 0²

= 144 + 0

∴AB² = 144

BC² = (13 - 13)² + (1 - 6)²

= 0² + (-5)²

= 0 + 25

∴BC² = 25

AC² = (1 - 13)² + (1 - 6)²

= (-12)² + (-5)²

= 144 + 25

∴AC² = 169

Now, AB² + BC² = 144 + 25

= 169

= AC²

∴AB² + BC² = AC²

Thus, (1,1) , (13,1) and (13,6) are the vertices of a triangle, and that too a right angled triangle.

yes these are points are of a right angled triangle triangle.

we can check it using distance formula