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When the stone at the height then it will have potential energy =mgh
as there is initial velocity =0
then kinetic enenrgy at h=0
if we drop the stone it acquires acceleration g.
we know that v square -u square =2as
v square=2gh
then final velocity v=root over 2gh
then kinetic energy=1/2mvsquare=gh
0 0 0
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