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A conical heap is formed when a farmer pours food grains on a ground .the slant height of heap is 35cm the circumference of the base is 132cm. what amount

of tarpaulin is needed to cover the grains? Farmer goes to the orphanage and gives half of the food grains for the children living there. how much grains farmer donoted ? list values you learn from this act of the farmer?

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Given: Circumference of thebase= 132 cm slant height = 35 cm

We need to get the volume of the cone. We need the radius of the cone.

Circumference = 2 π r r = circumference / 2π r = 132 cm / 2 * 3.14 r = 132 cm / 6.28 r = 21 cm

Volume of the cone = 1/3 π r² √l² - r² V = 1/3 * 3.14 * (21cm)² * √(35² - 21²) V = 1/3 * 3.14 * 441cm² * √1225-441cm V = 461.58cm² * √784cm V = 461.58cm² * 28cm V = 12,924.24 cm³

Surface area of the cone to know the measurement of the tarpaulin needed. Surface area = π r l + πr² SA = 3.14 * 21cm * 35cm + 3.14 (21cm)² SA = 2,307.9 cm² + 3.14 (441cm²) SA = 2,307.9 cm² + 1,384.74 cm² SA = 3,692.64 cm²

Tarpaulin = 3,692.64 cm²

Half of the grain given to orphanage = 12,924.24 cm³ ÷ 2 = 6,462.12 cm³