Answers

2016-04-13T14:38:46+05:30
We know that,
sec² a - tan² a = 1
(sec a- tan a)(sec a + tan a) = 1
(sec a- tan a) 1/3 = 1
(sec a- tan a) = 3
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2016-04-13T15:06:33+05:30
We have a trigonometric identity :
sec²a- tan²a =( sec a+tan a)(sec a-tan a) = 1
given,
sec a+ tan a =1/3
⇒(1/3)( sec a - tan a) = 1
⇒sec a - tan a =1/(1/3) = 3


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