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The difference between the outer lateral surface area and inner lateral surface area of a cylindrical metal pipe 28 cm long is 176 cm find the outer and

the inner radius of the pipe is made of 352 cm of metal


Let the outer radius be 'R' and the inner radius be 'r'. By using the formula 2×pi×h (R-r)=176 we will get that (R-r)=1 Now by using pi×h×(R^2-r^2)=352 we will get that (R+r)=4 using (R-r)=1 R=1+r In (R+r)=1+r+r=4 r=1.5 R=2.5
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