Free help with homework

Why join Brainly?

  • ask questions about your assignment
  • get answers with explanations
  • find similar questions

A wheel of radius 1 m rolls forward half a revolution on a horizontal ground. The magnitude of the displacement of the point of the wheel initially in

contact with the ground is? Ans is root pie sq +4 but how? When I am solving it, I get pie r but I guess here I've to use the formula on rotational motion.


Given, the radius of the wheel is 1m. so,its circumference is 2π m
when it rotates half, the initial point of contact is vertically above the final point of contact.thus,the three points form a right triangle.
by pythagoras theorem, we solve it to get the magnitude of displacement,which is the hypotenuse.
thus, d= \sqrt{4+  \pi ^{2} }
here's the answer!
pls mark as brainliest!
2 5 2
The Brain
  • The Brain
  • Helper
Not sure about the answer?
Learn more with Brainly!
Having trouble with your homework?
Get free help!
  • 80% of questions are answered in under 10 minutes
  • Answers come with explanations, so that you can learn
  • Answer quality is ensured by our experts