Free help with homework

Why join Brainly?

  • ask questions about your assignment
  • get answers with explanations
  • find similar questions


SecA+tanA=1/3 //as we know....sec^2A-tan^2A=1 //(SecA-tanA)(SecA+tanA)=1 //(secA-tanA)(1/3)=1 //SecA-tanA=3
2 5 2
We know the trigonometric identity: sec² A- Tan²A =1
this can be written as (secA - tanA)(secA +tanA) =1  since a²+b² = (a+b)(a-b)
let this be eq(1)
given, (secA+tanA)=1/3
by substituting in the above eq(1)
we get,
(1/3)(secA-tanA) =1
secA -tanA = 1/(1/3)
⇒sec A - tan A = 3 
1 5 1
The Brain
  • The Brain
  • Helper
Not sure about the answer?
Learn more with Brainly!
Having trouble with your homework?
Get free help!
  • 80% of questions are answered in under 10 minutes
  • Answers come with explanations, so that you can learn
  • Answer quality is ensured by our experts