Answers

2016-04-18T20:01:55+05:30

To find zeros, let

2x² - 9 = 0
∴(√2x)² - (3)² = 0
∴(√2x + 3)(√2x - 3) = 0
∴√2x+ 3 = 0        or            √2x - 3 = 0
∴x = -3/√2          or             x = 3/√2

Thus, zeros of the polynomial are -3/√2      and     3/√2









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