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A number when divided by a divisor leaves a remainder of 27. Twice the number divided by the same divisor leaves a remainder of 3. Find the divisor.



let q1 be quotient of first division and q2 be the quotient of second division, d be the divisor and let original number be num.
the 2 equations formed are:
1) num=d*q1+27

multiplying equation-1 by 2 and equating the equations gives us

shifting the d term on one side and numbers on the other 

taking d common from the left side


so d can either be 51 or one of its factor(17 or 3).
since we have a reminder of 27 in one case d cannot be less than 27.
so divisor is 51.
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