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A copper wire is bending in the form of a square having an area of 484 cm square. if the same wire is bend in the form of a circle, what is the area of

Area of square = side× side 484 = side× side therefore side = √484 side = 22 cm perimeter of square = 4× side = 4×22 =88 cm perimeter of square = perimeter of circle 88 cm = 2πr ∴ r = 88÷ 2π r = 14 cm area of circle = πr² ∴ area of circle = π×14×14 = 576 cm²

Given, area of square = 484 sq.cm s × s = 484 s =√484 = 22 cm then, the perimeter of square = 4 × s = 4× 22 = 88 cm perimeter of square = perimeter of circle 88 = 2πr 88 = 2 × 22/7 × r 88× 7/ 44 = r 14 cm = r required area of circle = πr² = 22/7 × ( 14)² = 22/7 × 196 = 22× 28 = 616 cm²