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When a speed of a car is v,the minimum distance over which it it can stopped is s.If the speed becomes nv,what will be the minimum distance over which it

can be stopped during same retardation?


So,the acceleration can be found out through the equation v²-u²=2as u²=2as
there a = u²/2s
new condition,same equation can be used
=n²s=minimum distance travelled

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