Answers

2016-04-23T07:07:42+05:30
The equation to be proved is n(n+1)(n+2)=6 times something.
For n=1,
LHS= 6
RHS= 6= LHS.
Let n=k hold true for any other +ve value.
Therefore, k(k+1)(k+2)=6m
Now to prove that n=k+1 is also true,
Substitute k+1 in place of n or k to get (k+1)(k+2)(k+3)
=(6m/k)*(k+3)
=6*[(m/k)*(k+3)]
=6 times something
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