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## Answers

For n=1,

LHS= 6

RHS= 6= LHS.

Let n=k hold true for any other +ve value.

Therefore, k(k+1)(k+2)=6m

Now to prove that n=k+1 is also true,

Substitute k+1 in place of n or k to get (k+1)(k+2)(k+3)

=(6m/k)*(k+3)

=6*[(m/k)*(k+3)]

=6 times something