Answers

2016-04-23T16:05:13+05:30
Let us consider 14^n end with the digit 0 and 5
therefore
5 divides 14 and 14^n
But the prime factors of 14 is (2*7) and 14^n is (2*7)^n
So, our assumption is incorrect.
Therefore , 14^n cannot end with the digit 0.
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