# If one root of the equation x²+px+q=0 is 4 times of the other root,then: a)p²-4q=0. b)4p²=q² c)25p²=4q. d)4p²=25q

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by Ash01

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by Ash01

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a+4a= -p

i-e, 5a= -p

Also,

a×4a = q

i-e,4a^2=q

Now,

4p^2=4×(5a)^2

=100a^2

25q=25×4a^2

=100a^2

So,4p^2=25q

Hence,option D is the correct choice.

Hope it helps.