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Let the numbers be x and y according to question x+y=1000..........(1) also, it is given that x^2-y^2=256000. using the identity a^2-b^2= (a+b)(a-b) we get (x+y)(x-y)= 256000 using equation 1 we get 1000(x-y)=256000 on further solving we obtain x-y= 256...........(2) add 1 and 2 you will get 2x=1256 so x=628 put value of x in equation 1 so you would get _ 628+y=1000 y=372
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find the values
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