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1. In a town of 10,000 families it was found that 40% families buy newspaper A, 20% families buy newspaper B and 10% buy C. 5% buy AB, 3% buy BC and 4% buy

AC. If 2% families buy all the three, find the number of families which buy i) A only ii) B only iii) none of A,BC.


1.4000 people buy A news paper
2. 2000people buy news paper B
3.2000 people doesn't buy any of the news paper.
1.Solution 40÷100×10000=4000
3.By adding all the people eho buys news paper we got the answer 2000
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