Answers

2016-04-24T17:55:33+05:30
Atoms in ------> (1) 1g of gold=3.05 × 10^21 atoms.........(2) 1g of na= 2.61 × 1022 atoms.............(3) 1g of li= 8.60 × 1022 atoms...............(4) 1g of cl2= 1.69 × 1022 atoms............... So, 1g of li has largest no. of atoms.
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2016-04-24T18:58:59+05:30
 1g of li has largest no. of atoms.
c)1g of li 
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