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2016-04-24T21:32:49+05:30

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Let deer be represented by d and visitors represented by v.
deer and visitors have one head each, so d + v = 39
a deer has 4 legs and a visitor has 2 legs, so 4d + 2v = 132

d + v = 39
4d + 2v = 132

d = 39 - v

4(39 - v) + 2v = 132
156 - 4v +2v = 132
-2v = 132 - 156
-2v = -24
v = -24/-2
v = 12

d = 39 - v
d = 39 - 12
d = 27

there are 12 visitors and 27 deer.

to check: 
d + v = 39
27 + 12 = 39
39 = 39

4d + 2v = 132
4(27) + 2(12) = 132
108 + 24 = 132
132 = 132
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2016-04-24T22:01:25+05:30
Let No.of visitors be x No.of deer's be y No.of heads = x+ y=39 No.of legs =2x+4y=132 Since visitor has two legs and deer have four. Plotting these lines on a graph gives you a point of intersection which tells the answer You can also find it by solving the above two equations. Which is x+y=39=>x=39-y Substitute in second equation 2x+4y=132=>x+2y=66 39-y+2y=66 Y=66-39=27 X=39-y=39-27=12 There fore the required answer is there are 12 visitors and 27 deer
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