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Hi there! Have questions about your homework? At Brainly, there are 60 million students who want to help each other learn. Questions are usually answered in less than 10 minutes. Try it for yourself by posting a question! :D

Let the roots of the given equation be 'a' &'b' . a+b=-(-7)/6=7/6. .....(1) ab=2/6=1/3. .....(2) Now,the required equation has roots: 1/a & 1/b. sum of roots,S=(1/a)+(1/b) =(a+b)/ab =(7/6)÷(1/3). {from 1 & 2} S =7/2. ...(3) product of roots,P=(1/a)×(1/b) =1/(ab) =1÷(1/3) P =3. ...(4) The required equation will be of the form: y^2 -Sy+P = y^2-(7/2)y+3=O [from 3 & 4] =2y^2-7y+6=0 Hence,the required equation is: 2y^2 - 7y + 6 = 0