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A man has two daughters and one son. The sum of the ages of his two daughters and one son is equal to age of the father. In 15 years the sum of the ages of

his children will be 1 and half times their father's age. What is the father's age now


Let the age of children be x \\
age of father will also be x \\
after 15 yrs  \\
age of children will be x+45(as there are 3 children so each ones age has increased to 15 yrs)
age of father = x+15
1.5(x+15) = x+45
1.5x+22.5 = x+45
1.5x-x = 45-22.5
0.5x = 23.5
x = 23.5/0.5
x = 47
so present age of father is 47yrs
0 0 0
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