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A research chemist wants to make 10.0L of gasoline containing 2.0% of a new experimental additive, one with 5.0% and the other with 6.0% are to be used. if

four times as much gasoline without additive as the 5.0% mixture is to be used, how much of each is neede?

a research chemist wants to make 10.0L of gasoline containing 2.0% of a new experimentaladditive. Gasoline without additive and two mixtures of gasoline with additive, on ]e with 5.0% and the other with 6.0% are used. if four times as much gasoline without additive as the 5.0% mixture is used, how much of each is needed

a research chemist wants to make 10.0L of gasoline containing 2.0% of a new experimentaladditive. Gasoline without additive and two mixtures of gasoline with additive, on ]e with 5.0% and the other with 6.0% are used. if four times as much gasoline without additive as the 5.0% mixture is used, how much of each is needed

x+y+z= 10 0*x+0.05*y+0.06*z=0.02*10=0.2 or, 5y+6z=20 further, x=4y putting this in first equation 5y+z=10 subtracting from the second equation: 6z-z =10 z=2 5y=8 y=1.6 x=6.4 use 6.4, 1.6 and 2 litres respectively of the three solutions. (answer)