Answers

2016-04-28T14:34:09+05:30
Given 4^ 2013
Let us take log 4^2013 
= log[(2)²]^2013    [∵ (a^m)^n = a^mn]
= log 2^ 4026        
= 4026 log2                [∵ logm^n = nlogm] 
= 4026 × 0.301           [∵ log2 = 0.301]
= 1211.826
∴ 4^2013 has 4 digits before decimal


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