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Let the height of tower be x u = 0m/s so let time to cover 5/9x of building be t sec so time taken to cover 4x/9 of the building = t - 1 sec

5x/9= 5(2t - 1) ...........(i) g = 10 so again s = ut +1/2gt² 4x/9 = 0 + 5(t - 1)² ..................(ii) dividing i and ii 5x/9/4x/9 =5(2t - 1) /5(t - 1)² ⇒5t² +5 - 10t = 8t - 4 ⇒5t² -18t +9 =0 solving t we get t = 3 sec and 0.6 sec

If total time of fall is t h=1/2 gt² fall in t-1 time period = h- 5/9h= 4/9h Thus, 4/9h = 1/2 g (t-1)² dividing first equation by the second t²/(t-1)² = 9/4 taking square root t/(t-1)= 3/2 2t=3t-3 t=3 (answer)