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Angle between two vectors is given as cosФ= V(A-B).V(A) / IV(A-B)I IV(A)I where V(A-B).V(A) means scalar product or the dot product and IV(A-B)I IV(A)I means product of modulus of vector V(A-B) and V(A) respectively.

Hence from this we get

cosФ= 2*1+2*1+2*1 / (√2²+2²+2²)(√1²+1²+1²) cosФ= 6/(2√3)(√3) cosФ= 6/6 cosФ=1 hence cosФ=1 at 0°,180° hence Ф=0° Ans