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Equivalent weight [E] of sulphuric acid = Molecular weight of sulphuric acid                                                                = M / (1×2) = M/2

So M = 2E
2M sulphuric acid means ,
1L solution contains 2M sulphuric acid
 = 2 × 2E Sulphuric acid
 = 4E Sulphuric acid = 4N Sulphuric acid

So the answer is b) 4N 
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