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Force of attraction b/w two point charges placed at a distance d is F. What distance apart should they be kept in the same medium so that force b/w them is

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Let us consider two point charges q1 and q2, placed at a distance d. Force of attraction, F = k (q1q2)/d²________(1) Now, if the force becomes F/3, then let the distance between the point charges be r Now, force of attraction, F' = F/3 = k (q1q2)/r²______(2) dividing equation, (1) and (2),we get 3 = r²/d² ⇒r² = 3 d² ⇒r = d√3 If the distance between them is d√3, the force will be F/3.

Consider two point charges q1,q2
At a distance D
Force between them is F = kq1q2/d^2
Let the distance between the two charges be r when the force between them is F/3
F/3 = kq1q2/r^2
Dividing equation 2 by equation by 1
1/3 = d^2/r^2
r^2 = 3(d^2)
r = √3 D
There fore when the distance between the two point charges is √3d the force becomes F/3