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2016-05-02T20:06:15+05:30

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In the given series,
a=0.9,
d=0.91-0.90=0.01,
n=100
Sum of the terms(S₁₀₀)=100/2[0.9+(100-1)0.01]
⇒S₁₀₀=50[0.9+99(0.01)]
⇒S₁₀₀=50(0.9+0.99)
⇒S₁₀₀=50(1.89)
S₁₀₀=94.5
Therefore,sum of the terms is 94.5.
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2016-05-04T09:18:47+05:30
Find the sum of following series,  X+y, x-y, x-3y, ......................, 22 terms
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