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A number when divided by a divisor leaves 27 as remainder Twice the number when divided by the same number leaves remainder 3.Find the divisor. Please



Let q1 be quotient of first division and q2 be the quotient of second division, d be the divisor and let original number be num.
The 2 equations formed are:
1) num=d*q1+27

Multiplying equation-1 by 2 and equating the equations gives us

Shifting the d term on one side and numbers on the other 

Taking d common from the left side


So d can either be 51 or one of its factor(17 or 3)
0 0 0
Actually it is 51 because the dividend is always greater than the remainder. Thanks
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