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ABC is a triangle ,D is the midpoint of BC,and AD is perpendicular to BC.Prove that area of triangle ABC = 1/2 multiplied by AD multiplied by BC



First ,area of triange abd and tri acd
                bd=cd  ......given
                 angle bda =angle cda.........given
          hence, triangle abd= triangle acd 
                 therefor  tri abc = 1/2 ad
1 3 1
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