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Assume that the electron in li2+ ion is in third orbit calculate the radius of the orbit and total energy of the electron



N=3.....Z=3.....by substituting the values.....in formula..r=n²h²/4Π²mZe².......we get the radius=1.587A°......& total energy=...-2Πr²me⁴Z²/n²h²......=...-13.6..ev/atom
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