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If the sum of zeroes of the polynomial x^2-(k-3)x+(5k-3) is equal to one fourth of the product of the zeroes find the value of k



For the polynomial x²-(k-3)x+(5k-3)

Sum of the roots = -b/a = (k-3)

Product of the roots = c/a = (5k-3)

As per the question, 
Sum of zeroes = 1/4( product of zeroes)

k-3 = 1/4(5k-3)

4k - 12 = 5k - 3

k = -9

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