Answers

2016-05-17T09:45:42+05:30
(a+b+c)^3=a^3+b^3+c^3+3×a(b^2+c^2)+3b(a^2+c^2)+3c(a^2+b^2)+6abc
7^3=151+3a(35-a^2)+3b(35-b^2)+3c(35-c^2)+6abc
343=151-3(a3+b3+c3)+105(a+b+c)+6abc
6abc=343-735+302=-90
abc= -15
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