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The distance between towns A and B is 300 km. One train departs from town A and another train departs from town B, both leaving at the same moment of time

and heading towards each other. We know that one of them is 10 km/hr faster than the other. Find the speeds of both trains if 2 hours after their departure the distance between them is 40 km.


we will assume that the speed of the first will be "x km/hrs"
Then according to the question :
the speed of the other train = "x+10 km/hrs"

We know that "speed = distance ÷ time"
→ the speed of the first train :
⇒ x = distance/2 (here we are using 2 hours as said in the question) 
The distance = 2x
2x will be the distance covered by the first train

For the distance covered by the second train:
(we need to only need to add 10 for the distance covered by first train) 
⇒ 2(x+10)

For the length of the tracks :
"distance travelled by first train + distance travelled by second train + distance between them"
2x+2(x+10)+40 = 300km
4x+20+40 = 300km
4x = 300km - 60
4x = 240
x = 240 ÷ 4
x = 60 km/hrs
∴ speed of the first train = 60 km/hrs 
→ for the speed of the second train :
⇒ x+10
⇒ 60+10 = 70 km/hrs
∴ the speed of the second train = 70 km/hrs
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