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See figure. Distance of plane 1 (East) at time t hours is (620 * t) km

Distance of Plane2 at time t=0 is 310 km as it is at Lake Winnipeg

Distance of Plane 2 at time t hours is = 310 + 560 * t km

The triangle formed by Plane2, plane1 and winnipeg is a right angle triangle.

Let the Distance between two planes be D

So D² = ( 620 t )² + (310 + 560 t)²

As time t increases from 0, then D increases. Let us see when D becomes 1000 km. Substitute D = 1000 km in the above equation.