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A rectangilar safe is to be made of steel of uniform thickness, including the door the inside dimensions are 1.20 m ,1.20 m and 2.00 m if the volume of the

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The INSIDE dimensions of the rectangular safe : Length L = 1.20 m Breadth B = 1.20 m Height H = 2.00 m Let thickness of safe be t meters

To get the outside dimensions: add t on each side of a dimension.( left side and right side for widht and length. Also at top and bottom for height). so each dimension becomes plus 2t.

find t by solving the equation. The roots of this polynomial could be possibly factors of +- 1.25 / factors of 8

t = 0.0886 meters or 0.0887 meter , that is 8.86 cm or 0.0887 cm approx.

t is so small that t³ is very small compared to t² and t. SO neglect the t³ term and solve the equation using te quadratic equation formula. The answer u get will be very close the actual one.