Answers

2014-08-22T13:28:39+05:30

This Is a Certified Answer

×
Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
it is same 100 m/sec

v = final velocity     u = initial velocity     a = acceleration 
S = distance traveled      t = time traveled
suppose at the top point it reaches, its height is H.

A body goes up to a height during the upward journey
            v = u + at      =>  0 = u - g t        =>  t = u/g  : time to reach the top
            v² - u² = 2 a S    =>  0² - u² = 2 (-g) H  => u² = 2 g H    => H = 1/2u²/g

OR,          H = ut + 1/2 a t²  =  u*u/g -1/2 g (u/g)² = u²/g - 1/2 u²/g

       So H = 1/2 u² / g    ------ equation 1

A body falls freely from height H: then
           v = u+at    =>    v = 0+ g t  = gt
           v² - u² = 2 a S  =>  v² - 0 = 2 g S      =>  S = 1/2 v² / g

   If the body travels a distance H on the way down then, above formula is:
               H = 1/2 v² / g                --- which is same as equation 1

So velocity at a height H from ground on the way up
           = velocity at same height H from ground on the way down

1 5 1