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A boy throws a stone vertically up and catches it after time "t" seconds. what is the maximum height reached by the stone?

a)gt²÷2 b)gt²÷4 c)gt²÷8 d)gt²÷16

the answer in my textbook is gt²÷8

please solve it urgently.



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The stone takes same time to go up to the top and to return from the top. Hence, the time to return or descend from the top is = t/2 seconds.

In this time the stone traveled on the descent:

s = 0 t/2 + 1/2 g (t/2)² =  (g t²) / 8

0 0 0
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