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2 paper screens A to B are separated by 150 m. A bullet pierces A and then B. The hole in B is 15cm below the hole in A. If the bullet is travelling

horizontally at the time of hitting A, then the velocity of the bullet at A is (g = 10ms raised to -2) find velocity of b



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Time duration for fall of bullet by 15 cm :
     S = u t + 1/2 at²  =>  0.15 = 0 t + 1/2 * 10 * t²
     So  t = √0.03 sec = 0.1732 sec

Distance traveled horizontally in this time period: 150 meters
Velocity at A is the constant horizontal velocity of the bullet.
         = 150 meters / 0.1732 sec = 866.050 m/sec

Vertical component of velocity of bullet when it reaches paper B
         v = u + at  =>  v = 0 + 10m/sec² * 0.1732 sec = 1.732 m/s

Total Speed of bullet when it pierces paper B :
           V  = √( 866²+1.732² )  =  866.0525 m/sec

2 5 2
kvnmurty sorry i don't want velocity of b i want the velocity of a convert into that is convert g=10ms raised to -2 into 100 square root of 3 ms-1
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